gulp-strip-debug-arbitrary

Strip alert, debugger and arbitrary statements (e.g. console with property whitelist) from JavaScript code with strip-debug-arbitrary

Install

1$ npm install --save berstend/gulp-strip-debug-arbitrary

Usage

1var gulp = require('gulp');
2var stripDebug = require('gulp-strip-debug-arbitrary');
3
4gulp.task('default', function () {
5	return gulp.src('src/app.js')
6		.pipe(stripDebug())
7		.pipe(gulp.dest('dist'));
8});

API

By default alert, and debugger statements are being stripped and without additional parameters all console statements as well.

The latter can be overwritten by adding some parameters to the stripDebug() method.

Stripped means the statements are replaced by void 0 which UglifyJS can later remove altogether.

stripDebug(id, whitelist)

id

Type: string

Default: console

Optional: Pass the name of the statement to remove (e.g. "log"), if none is given "console" is being used.

whitelist

Type: array

Default: []

Optional: Pass an array of properties to exclude (e.g. ["warn", "error"])

License

MIT © Sindre Sorhus & berstend